| Divider value when the Uart clock source is selected as FCLK/n. ’n’ is determined by UCON0[15:12], UCON1[15:12], UCON2[14:12].
 UCON2[15] is FCLK/n Clock Enable/Disable bit.
 For setting ‘n’ from 7 to 21, use UCON0[15:12],
 For setting ‘n’ from 22 to 36, use UCON1[15:12],
 For setting ‘n’ from 37 to 43, use UCON2[14:12],
 UCON2[15]: 0 = Disable FCLK/n clock. 1 = Enable FCLK/n clock.
 In case of UCON0,
 UART clock = FCLK / (divider+6), where divider>0.
 !!!(1)UCON1, UCON2 must be zero.
 ex) 1: UART clock = FCLK/7, 2: UART clock = FCLK/8
 3: UART clock = FCLK/9, … , 15: UART clock = FCLK/21
 In case of UCON1,
 UART clock = FCLK / (divider+21), where divider>0.
 !!!(2)UCON0, UCON2 must be zero.
 ex) 1: UART clock = FCLK/22, 2: UART clock = FCLK/23
 3: UART clock = FCLK/24, … , 15: UART clock = FCLK/36
 In case of UCON2,
 UART clock = FCLK / (divider+36), where divider>0.
 UCON0, UCON1 must be zero.
 ex) 1: UART clock = FCLK/37, 2: UART clock = FCLK/38
 3: UART clock = FCLK/39, … , 7: UART clock = FCLK/43
 
 !!!(3)If UCON00/1[15:12] and UCON2[14:12] are all ‘0’, the divider will be
 !!!(3)44, that is UART clock =FCLK/44
 !!!(3)Total division range is from 7 to 44.
 
 
 
 想问一下 (1)第一处的问题   UCON1, UCON2 must be zero. ?  到底是 UCON1[12--15] UCON2[12--14]  为0 吗?
 (3) 1. UCON00/1[15:12]  ??? 是要表示 UCON0[15:12]的意思吗?  2. 是不是只要满足  If UCON00/1[15:12] and UCON2[14:12] are all ‘0’   的时候不管  其它不管怎么设置都是  FCLK/44
 
 (4):  在裸奔3的代码中init_uart 中 ,  UCON 0/1/2 =0x245  那么UART 的使能 UCON2[15]=0  莫非URAT无源可以工作?
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